HI I have faced a typical exception while running my application.
my application contains 3 forms 1.login,2.Main form 3.dataentry form
in my application first i will going through some id and then in the main form menu item i call the dataentry form.upto that is fine.
there is a logout menuitem in my main form.if i logout then the login form will again appear so i will login using some other id now if i call the dataentry form the exception occuring from where i was calling the form. the exception was
An unhandled exception of type 'System.ArgumentException' occurred in system.drawing.dll
Additional information: Invalid parameter used.
the form was calling using show dialog and i'm also using the dispose method after closing the form.
can any one tell the solution to this.here i'm providing the code of the form.Thanks in advance
-regards
GRK
calling the dataentry from from main form
Try Dim trFrmSExcuse As New FrmSRegntrFrmSExcuse.ShowDialog()
trFrmSExcuse.Dispose()
Catch ex As ExceptionMessageBox.Show(ex.Message, strCaption, MessageBoxButtons.OK, MessageBoxIcon.Error)
End Try
error occuring while opening the form second time
ZimY
Alexandr Vishnyakov
What line of code is throwing the error
Run your app in debug mode and it should stop and Highlight the line that is causeing the error....if it does not then you will have to step into the code line by line util the error occurs
MechEng85
HI
now the problem was solved. the first form is not disposing while closing so when again i open it then the error come so i'm externally calling the dispose method.now it is cleared. thank you verymuch for your replies
Wee Bubba
It is highlighting the frme.showdialog() line