Dear Friend
I want to implement thread in C# for mean,median and mode functions.
in which the calculation will be in the following sequance
1. Mean [x' = (x/n)]
2. Median [M = ((n+1)/2)]
3. Mode [z = (2M+3x')]
can you help me.
Thanks in advance
Dear Friend
I want to implement thread in C# for mean,median and mode functions.
in which the calculation will be in the following sequance
1. Mean [x' = (x/n)]
2. Median [M = ((n+1)/2)]
3. Mode [z = (2M+3x')]
can you help me.
Thanks in advance
Multithreading in C#
mobigital
Yes Ilyas you are right but I was also right
, because its understood that a function to calculate mean will need to have some parameters on which it has to do work. Its quiet obvious.
Second, Do you really think that he's doing some professional work I think he's just trying Multithreading. How it works so this idea came to his mind and he started working on that. Thread is costly and we don't deny from this reality! But I think hes just doing practise with it.
Best Regards,
Rizwan
constm
thanks for your co-operation on this matter but what i would want i have 3 different function mean,median,mode and the function mean will execute first and then median and at last mode how can i do this can you.
thanks.
Rainadaman
You can create and start thread who do the work for you:
Thread meanThread = new Thread(new ThreadStart(CalculateMean));
meanThread.Start();
private void CalculateMean(/* Paramters here*/)
{
// Logic here
}
Note: Do no forget to reference System.Threading
Same for others!
I hope this will help!
Best Regards,
Rizwan
SAinet
That's not correct. You need to use ParameterizedStart method if you wanted to start a thread which calls a method which contains parameters as inputs.
I wouldnt understand why you wish to start up threads to do calculations - unless they REALLLY take a LOOONNGG time to complete. threading is expensive so use it only when you think you need to.
Crasch
See the Thread.Join() function, it'll do work for you. Better explore MSDN to see what does it do.
I hope this will help you but in case of any problem you can come back!
Best Regards,
Rizwan Ahmed