Cannot implicitly convert type 'uint' to 'int'

I try to declar this statement:

private static int[] MyArr = {0x243F6A88, 0x85A308D3, 0x13198A2E};

And got this error

What wrong am I

Thank

soanfu
If you're coming from a C++ background, C# is much more strict with types of literals. 0x85A308D3 is not considered an int because the top bit is high, forcing it to upcast to a uint so it will fit, despite legally representing a valid int value. Use the unchecked keyword to avoid the error. For example:

private static int[] MyArr = {0x243F6A88, unchecked((int)0x85A308D3), 0x13198A2E};
niroshanonline
Simply, the value you're attempting to assing to an int value exceed it's "range" capacity.

Integral values expressed using hexadecimal notation are interpreted as UNSIGNED values.

You can use an unchecked explicitly cast or choose a wider type, depending on your needs.
Ri-Karou
OK its work

Thank you very much
Sergey Astapov
Hexadecimal constant is interpreted as unsigned integer, you need to add casting:

private static int[] MyArr = {(int)0x243F6A88, (int)0x85A308D3, (int)0x13198A2E};
tcarff
Yes I'm agree... maybe my post was a bit confusing, I've already expressed the "range check rule" in the first period of my former post.
johnTheDeveloper

Mr. BogoMips wrote:

Integral values expressed using hexadecimal notation are interpreted as UNSIGNED values.

Not necessarily. The type depends on the value you specify. The default type rules for numeric literals are the same whether you use decimal or hexadecimal representation.
Cannot implicitly convert type 'uint' to 'int'