how can we see output?

how can we see output?

• ogagnol

  i mean in a console application when we make any program to pirnt a number 5 times then it automaically check tha errors in visual C#. but when we press E5 to buil the console application it it appears on the screen only for 1-2 second means not for enough time to see the output . what is the command in console application by which output should be visible atleast for 5 second.
  
  
  

• Irina777

  Hi,

  you can use System.Threading.Thread.Sleep(5000); which will pause the main thread for 5 seconds before allowing the console to exit. As mentioned you could also use Console.ReadLine() but that would then require you to press enter for the console application to exit.

  Mark.

  
  
  

• GarethJ - MSFT

  Console.ReadLine() will wait for the Enter key to be pressed
  
  

• papadi

  The code compiles on my machine. There is a bug in the code which can be corrected by changing the line.
  
  Console.WriteLine("{0}: {1]",ctr,line);
  
  to
  
  Console.WriteLine("{0}: {1}",ctr,line);
  
  

• Spangltk

  thanx my friends , i tried all the methods all are helpful to see the output............... i'll post more question here as i'll face problem.
  
  
  

• Linda2270

  Hi,

  do you mean ouptu when the program in running Is it a windows application or console app You should be able to look at the Output window in visual studio to see any output you have wrtitten.

  Mark.

  
  
  

• iSerg

  My dear friend

  Instead F5 do Ctrl + f5. thats it.

  
  
  

• Shyamal Patel

  in this console application program an error is shown in visual C# 20005 n the error is 'System..IO.StreamReader' does not contain a definition for 'ReadLine' which is highlighted by blue color....... plz tell me the solution
  
  
  
  using System;
  using System.Collections.Generic;
  using System.Text;
  using System.IO;
  
  namespace program
  {
  class Program
  {
  public static void Main(string[] args)
  {
  try
  {
  int ctr=0;
  if (args.Length<=0)
  {
  Console.WriteLine("Format listIT filename");
  return;
  }
  else
  {
  FileStream f= new FileStream(args[0],FileMode.Open);
  try
  {
  StreamReader t= new StreamReader(f);
  String line;
  while ((line = t.ReadLine() )!=null)
  {
  ctr++;
  Console.WriteLine("{0}: {1]",ctr,line);
  }
  f.Close();
  }
  finally
  {
  f.Close();
  }
  }
  }
  catch(System.IO.FileNotFoundException)
  {
  Console.WriteLine("ListIT Could not Find the File",args[0]);
  }
  catch(Exception e)
  {
  Console.WriteLine("Exception : {0} \n\n",e);
  }
  
  
  
  
  }
  }
  }
  
  
  
  
  
  
  
  
  
  
  
• how can we see output?