how to take numbers from int and put them on table 1 by one

how to take numbers from int and put them on table 1 by one

• Carlos Figuera.

  What have you tried so far

  Thanks,

  Ayman Shoukry

  VC++ Team

  
  
  

• Rodolfo Montero

  peteyy wrote:

  i wasnt able to make that work :(

  You couldn't make my code work Really Because I tested it before I posted it here. What compiler are you using Did you include these headers

  #include <iostream> #include <string> #include <algorithm>

  
  
  

• zille

  I think this is what you want:

  int toint(int val) { return val - '0'; } int _tmain(int argc, _TCHAR* argv[]) { std::string val; std::cin >> val; std::reverse(val.begin(), val.end()); std::vector<int> array(val.length(), 0); std::copy(val.begin(), val.end(), array.begin()); std::transform(array.begin(), array.end(), array.begin(), toint); return 0; }

  
  
  

• spattewar

  i wasnt able to make that work :(
  
  is there a simple way to move numbers from Char to  an  Integer table.... like 12345 would put 5 to int[0]spot, 4 would go to int[1] spot... and so on.
  
  help would be appriciated, since im really stuck on this :(
  
  

• tulip-pcsc

  So you can learn by example.  Not as elegant as Marius' answer ... I don't use the Standard C++ lib that deeply.
  
  int main()
  {
      string s;
      cout << "Enter a string of digits: " << endl;
      getline( cin, s );
      vector<int> int_table;
      for( size_t i = 0; i < s.length(); i++ )
      { 
          if( s[ i ] >= '0' && s[ i ] <= '9' )
          {
             int_table.push_back( s[ i ] - 48 ); // subtract ascii of '0' to 0-base values
          }
          else
          {
              cerr << "Ignoring invalid character: " << s[ i ] << endl;
          }
      }

      for( size_t i = 0; i < int_table.size(); i++ )
      {
          cout << "int_table[" << i << "]=" << int_table[ i ] << endl;
      }
  }
  

  
  

• Anthony von LA

  Hi.. i tried this with string... so i would read the given number into string.. then move then re arrange it bacwards... and then putting it into int. here's the code:
  
  

  #include <iostream>
  #include <sstream>
  #include <string>
  
  using namespace std;
  
  int main() {
  
  	string numbers;
  	string temp;
  	int arranged[20];
  	
  	cout<<"give numbers: ";
  	cin>>numbers;
  
  	for(int i=numbers.length(), j=0; i>0; i--, j++) {
  			std::istringstream help(numbers.substr(i-1,1));
  			help >> arranged[j];
  			cout<<arranged[j];
  	}
  }

  
  but the problem with this code is that i cant multiple those re arranged numbers one by one.... for that i tried this code :
  
  #include <iostream>
  #include <sstream>
  #include <string>
  
  using namespace std;
  
  int main() {
  
  string numbers;
  string temp;
  int total;
  int arranged[20];
  int multiple []={7,3,1,7,3,1,7,3,1,7,3,1,7,3,1,7,3,1,7,3};
  
  cout<<"give a number: ";
  cin>>numbers;
  
  for(int i=numbers.length(), int j=0; i>0; i--, j++) {
  std::istringstream help(numbers.substr(i-1,1));
  help >> arranged[j];
  total+= help*multiple[j];
  cout<<arranged[j];
  cout<<total;
  }
  
  return 0;
  }
  
  it gives error : C2676: binary '*' : 'std::istringstream' does not define this operator or a conversion to a type acceptable to the predefined operator
  
  
  
  
  
• how to take numbers from int and put them on table 1 by one